2k^2-14k+12=0

Solution for 2k^2-14k+12=0 equation:

2k^2-14k+12=0

a = 2; b = -14; c = +12;
Δ = b2-4ac
Δ = -142-4·2·12
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-10}{2*2}=\frac{4}{4}
=1
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+10}{2*2}=\frac{24}{4}
=6
$